Circuitos Magneticos Ejercicios Resueltos Apr 2026

Circuito magnético equivalente: (fmm = \phi_1 \mathcalR_1 + \phi_2 \mathcalR_2 = 2\phi_2 \mathcalR_1 + \phi_2 \mathcalR_2) [ fmm = 400 \cdot 1.5 = 600 , \textA·v ] [ 600 = \phi_2 (2\cdot 331572 + 1.326\times 10^6) = \phi_2 (663144 + 1.326\times 10^6) ] [ 600 = \phi_2 (1.989\times 10^6) \implies \phi_2 \approx 3.016\times 10^-4 , \textWb ] [ \phi_1 = 2\phi_2 \approx 6.032\times 10^-4 , \textWb ] Enunciado : Circuito magnético con (l=0.25, \textm), (A=8, \textcm^2), (N=150). Al aplicar (I=2, \textA), se mide (\phi = 1.2\times 10^-3, \textWb). Calcular (\mu_r).

Reluctancias: [ \mathcalR_1 = \frac0.2\mu_0 \cdot 800 \cdot 6\times 10^-4 = \frac0.24\pi\times 10^-7 \cdot 800 \cdot 6\times 10^-4 ] [ \mathcalR_1 = \frac0.26.0319\times 10^-7 \approx 331572 , \textA·v/Wb ] [ \mathcalR_2 = \frac0.4\mu_0 \cdot 800 \cdot 3\times 10^-4 = \frac0.43.0159\times 10^-7 \approx 1.326\times 10^6 , \textA·v/Wb ] circuitos magneticos ejercicios resueltos

Por simetría, (\phi_2 = \phi_3), (\phi_1 = \phi_2 + \phi_3 = 2\phi_2). Circuito magnético equivalente: (fmm = \phi_1 \mathcalR_1 +

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