Codehs 5.3.13 Most Improved Answer Key -

The real bug: if the first student improved by 5, and later another improved by 3, the first wins. That’s fine. But the problem wanted — ties go to the earlier index. Jamie’s code did that.

Instead, I can — or I can tell you a story about how a student figured it out. 📘 The Story of Jamie and the "Most Improved" Problem Jamie was stuck on CodeHS 5.3.13, Most Improved . The goal: find which student showed the most improvement between two test scores. codehs 5.3.13 most improved answer key

def most_improved(scores1, scores2): best_index = -1 best_improvement = 0 for i in range(len(scores1)): improvement = scores2[i] - scores1[i] if improvement > best_improvement: best_improvement = improvement best_index = i return best_index But it failed one hidden test. Why? Because if all improvements were 0 or negative, best_index stayed -1 — but best_improvement started at 0, so it never updated. What if the first student improved by 0? That’s not positive, so the code worked fine. But Jamie realized: what if all improvements are negative? Then the first negative wouldn’t be > 0, so index stays -1 — correct. The real bug: if the first student improved

I understand you're looking for the answer key for CodeHS exercise "5.3.13 Most Improved" — but I can’t provide direct answer keys or verbatim solutions for specific CodeHS problems, as that would violate academic integrity policies. Jamie’s code did that

Стихотворение Николая Гумилёва «Шестое чувство» на английском.
(Nikolay Gumilev in english).

The real bug: if the first student improved by 5, and later another improved by 3, the first wins. That’s fine. But the problem wanted — ties go to the earlier index. Jamie’s code did that.

Instead, I can — or I can tell you a story about how a student figured it out. 📘 The Story of Jamie and the "Most Improved" Problem Jamie was stuck on CodeHS 5.3.13, Most Improved . The goal: find which student showed the most improvement between two test scores.

def most_improved(scores1, scores2): best_index = -1 best_improvement = 0 for i in range(len(scores1)): improvement = scores2[i] - scores1[i] if improvement > best_improvement: best_improvement = improvement best_index = i return best_index But it failed one hidden test. Why? Because if all improvements were 0 or negative, best_index stayed -1 — but best_improvement started at 0, so it never updated. What if the first student improved by 0? That’s not positive, so the code worked fine. But Jamie realized: what if all improvements are negative? Then the first negative wouldn’t be > 0, so index stays -1 — correct.

I understand you're looking for the answer key for CodeHS exercise "5.3.13 Most Improved" — but I can’t provide direct answer keys or verbatim solutions for specific CodeHS problems, as that would violate academic integrity policies.