A car travels 20.0 km due north and then 35.0 km in a direction 60.0° west of north. Find the magnitude and direction of the car's resultant displacement.
Using Newton's second law:
Let's break down the displacement into its north and west components:
So, the magnitude of the resultant displacement is 48.2 km, and its direction is 38.3° south of west. A car travels 20
The resultant displacement is:
North component: 20.0 km + 35.0 km * cos(60.0°) = 20.0 km + 17.5 km = 37.5 km West component: -35.0 km * sin(60.0°) = -30.3 km
a = F / m = (mg * sin(30.0°)) / m = g * sin(30.0°) = 9.80 m/s^2 * 0.500 = 4.90 m/s^2 The resultant displacement is: North component: 20
:
The direction is:
A 3.00-kg block is pushed up a frictionless ramp that makes an angle of 30.0° with the horizontal. Find the block's acceleration. A car travels 20
The force acting on the block is:
F = mg * sin(30.0°)