Solucionario Introduccion Al Algebra Lineal Howard Anton 5ta Edicion <SIMPLE — 2027>

| 1 2 -1 | 3 | | 2 -1 1 | 2 | | 1 1 1 | 1 |

Solución:

u · v = (2)(1) + (3)(-2) = 2 - 6 = -4

det(A) = 2(4 - 1) - 1(2 - 3) + 3(1 - 6) = 2(3) - 1(-1) + 3(-5) = 6 + 1 - 15 = -8 | 1 2 -1 | 3 | |

Solución:

La matriz diagonalizada es: